What is the probability of producing a child that will phenotypically resemble the first parent listed?
a. AaBbCcDd x aabbccdd
b. aabbccdd x AABBCCDD
c. AaBbCcDd x AaBbCcDd
d. aabbccdd x aabbccddWhat is the probability of producing a child that will phenotypically resemble the first parent listed?
First you can split the genotypes into individual gene. Then you calculate the probability of the crosses to have a child with the same genotypes as the first parents.
a.
Aa x aa --%26gt; 1/2Aa : 1/2aa
Bb x bb --%26gt; 1/2Bb : 1/2bb
Cc x cc --%26gt; 1/2Cc : 1/2cc
Dd x dd --%26gt; 1/2Dd : 1/2dd
The probability of a child with genotype AaBbCcDd = 1/2 x 1/2 x 1/2 x 1/2 = 1/16
b. 0 x 0 x 0 x 0 = 0
c. 1/2 x 1/2 x 1/2 x 1/2 = 1/16
d. 1 x 1 x 1 x 1 = 1 (All would be aabbccdd)
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